Ovid's and Shakespeare's Epitaphs
Three epitaph words with gematric values of
WILLIAM
I. 3 WORDS
II. 3+6+1 WORDS
I. 3 WORDS
1.
There are three words in the epitaph which have the same
gematric values as WILLIAM:
GOOD FREND FOR IESVS SAKE FORBEARE |
TO DIGG THE DVST ENCLOASED (74) HEARE. |
BLESTE BE YE MAN YT SPARES (74) THES STONES |
AND CVRST BE HE
YT MOVES MY BONES
(52). |
74 is the numeric sum (NS) of
WILLIAM, 52
its factoral sum (FS):
|
W |
I |
L |
L |
I |
A |
M |
|
NV |
21 |
9 |
11 |
11 |
9 |
1 |
12 |
74 |
The numeric values (NV) of WILLIAM are characterised by inversions. The
ratio
The combined numeric and factoral values are:
|
W |
I |
L |
L |
I |
A |
M |
sm |
NV |
21 |
9 |
11 |
11 |
9 |
1 |
12 |
74 |
FV |
10 |
6 |
11 |
11 |
6 |
1 |
7 |
52 |
sm |
31 |
15 |
22 |
22 |
15 |
2 |
19 |
126 |
2.
The 4values of the three
words are:
let. |
|
NS |
FS |
sm |
FV1 |
FV2 |
sm |
tot. |
9 |
ENCLOASED |
74 |
59 |
133 |
39 |
59 |
98 |
231 |
6 |
SPARES |
74 |
47 |
121 |
39 |
47 |
86 |
207 |
5 |
BONES |
52 |
37 |
89 |
17 |
37 |
54 |
143 |
20 |
|
200 |
143 |
343 |
95 |
143 |
238 |
581 |
343 =
7*49; 238 = 7*34; 581 = 7*83 |
The three words consisting of 20 letters have an average numeric value (NV) 10. The 20 letters correspond to twice 10 points in two
tetractyses.
The NS+FS result 343 is 7*7*7,
representing the elements of the three sides of the tetractys:
|
3.
The
three FS are prime so
that their FV are identical. The factors of 143 are 11*13. As 2*11*13 they can form an octahedron
from two axes of double
rhombi:
|
An octahedron looks like an urn to contain the ashes of a deceased
person. Shakespeare thus feels in safe rest.
4.
The sum of 581 = 7*83 forms part of
the total sum 3320
= 40*83.
5.
To assure posterity of the spelling of his name such as he
would like to be remembered SHAKESPEARE might have used the spellings FORBEARE and HEARE.
6.
Because of his love for the hexagram and the tetractys
Shakespeare may have been born and died on the same day, the 23rd of
April. 234 consists of the product 13*18, representing
13 elements of the three hexagonal axes and 18 of the three
sides of the tetractys:
|
Also the year 1616 points to the double circle of the hexagram,
because of the midpoint and twice 6 points on the circle line. The following
graphic shows the second 16
inverted as 61 because the circle has to be drawn after the
completion of the hexagram; F means area size:
|
1. The three
words can be enlarged, first by WILLIAM:
|
NS |
FS |
sm |
FV1 |
FV2 |
sm |
tot. |
3 words |
200 |
143 |
343 |
95 |
143 |
238 |
581 |
WILLIAM |
74 |
52 |
126 |
39 |
17 |
56 |
182 |
|
274 |
195 |
469 |
134 |
160 |
294 |
763 |
469 =
7*67; 294 = 7*42; 763 = 7*109 |
The NS+FS and FV1/2 of WILLIAM
are like the corresponding results of the 3 words divisible by 7. The total 7*109 can be
related to the 7
points of the hexagon and 10 points of the tetractys or,
alternatively, to its 10 points
and 9 triangles. The two numbers can
represent the ratio 1:3 of the two concentric circles of the hexagram.
2. The 4v-sum 182 connects
WILLIAM
with the NS 182 of SATOR OPERA TENET and IESUS CHRISTUS. 294 is the NS+FS of IESUS CHRISTUS.
|
ZS |
FS |
sm |
FW1 |
FW2 |
sm |
GS |
ROTAS |
69 |
54 |
123 |
26 |
11 |
37 |
160 |
OPERA |
52 |
40 |
92 |
17 |
11 |
27 |
120 |
TENET |
61 |
61 |
122 |
61 |
61 |
244 |
244 |
sm |
182 |
155 |
337 |
104 |
83 |
187 |
524 |
IESUS |
70 |
36 |
106 |
14 |
10 |
24 |
130 |
CHRISTUS |
112 |
76 |
188 |
15 |
23 |
38 |
226 |
sm |
182 |
112 |
294 |
29 |
33 |
62 |
356 |
total |
364 |
267 |
631 |
133 |
116 |
249 |
880 |
The results of the previous 4 words + above 5 words are:
4 words |
274 |
195 |
469 |
134 |
160 |
294 |
763 |
5 words |
364 |
267 |
631 |
133 |
116 |
249 |
880 |
sm |
638 |
462 |
1100 |
267 |
276 |
543 |
1643 |
462:638 = 22*( |
There are three remarkable results:
3. First, The two ratio
numbers 21 and 29 refer to the 9 diametric elements of
the hexagram, which can be numbered from 1 to 5 and 1 to 3:
|
|
The numbers can stand for two double
rhombi which can be formed into a cross and fitted into an octahedron.
The ratio 21:29 is the same as the NS+FS of WILLIAM and
SHAKESPEARE: 126:174 = 6*(21:29).
4. Second, the inverted
numbers 267 and 276 both refer to the double
aspect of 26 and 27 elements of the
octahedron: 6 corners, 12 edges or lines and 8 areas. These
outer elements are completed by 1 element of volume. The
sum 543 = 3*181 refers to the three
double rhombi of the hexagram, which contain 8 lines of the
frame and 2 lines across.
5. Third,
the double aspect of 26+27
elements is confirmed by the factor 53
of the total 4v-sums.
However, just as important is the meaning of the single digits 5 and 3, which are the
radial elements of the two concentric circles:
|
The numbers 5 and 3
represent the ratio of 3:1 area units which corresponds to the
second factor 31. The
numbers 3 and 1 symbolize the Christian trinity of one God in
three Persons.
There are three sums that contain the
factor 53:
|
NS |
FS |
sm |
FV1 |
FV2 |
sm |
tot. |
ENCLOASED |
74 |
59 |
133 |
39 |
59 |
98 |
231 |
SPARES |
74 |
47 |
121 |
39 |
47 |
86 |
207 |
sm |
148 |
106 |
254 |
78 |
106 |
184 |
438 |
IESUS |
70 |
36 |
106 |
14 |
10 |
24 |
130 |
sm |
218 |
142 |
360 |
92 |
116 |
208 |
568 |
142 = 2*71; 568 = 8*71 |
The three words allow the conclusion
that Jesus will take care of Shakespeare's enclosed bones. The 20 letters of the three words have the average NV+FV 18, which is
the number of letters of WILLIAM SHAKESPEARE. 71 is the FS of SHAKESPEARE. The FS
142 is the average sum of the other three sums. It is
the 4v-sum of the numbers 1-10:
|
NS |
FV |
sm |
FS |
FV |
sm |
tot. |
1-10 |
55 |
16 |
71 |
46 |
25 |
71 |
142 |
The double sum 71 can be referred to the 2*8 frame elements of the double rhombus:
|
6. The factor 31 is contained
in the 4v-sum of MARIA:
|
NS |
FS |
sm |
FV1 |
FV2 |
sm |
MARIA |
40 |
32 |
72 |
11 |
10 |
93 |
93 = 31*3 |
Shakespeare is highly devoted to the
Virgin Mary. He understands that she has enabled the redemption of mankind by
Jesus Christ. Therefore her 4v-sum has to be put before the total so far
established: 31*(
|
If one double rhombus is given one
midpoint and the second two, the frame of the cross of doublerhombi consists of
31 elements:
|
7. It should be
remembered here that Ovid determined the factors 35 (5*7) and 31 in the FS
1085
of his epitaph. Both FS 1085 + 971 = 2056 = 8*257 > FV 263 mean the same relation
between elements and area units (F), in this case referring
to points of the double rhombus:
|
The FV 263 can be understood either as 2*63 or 26*3. In both cases the result are three octahedra,
composed of 3*2 double rhombi of 21 elements for each double rhombus and 26 elements for each octahedron.
Written: April/June 2014